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Newbie here.
I need to drain the fuel that’s been sitting for a decade in my 1963 Pontiac Tempest LeMans. A normal siphon or transfer pump should do the job, I guess. But here’s a technique from the ’63 GM Tempest Shop Manual that has me stumped:
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- “1. Insert a length of hose (Fig. 8-6 for details) into the gas tank, pipe nipple end first, until weighted end of hose rests on bottom of tank.
- “2. With chuck of air hose inserted into hose slit, a short blast of air will cause the gas to flow.”
A PDF of Fig. 8-6 is attached.
OK, there’s a pipe nipple jammed into one end of a 1/2″ drain hose as a weight–I get that. But if the overall length of the hose is approx. 10″, per diagram–a dimension that would put the entire apparatus down the filler tube, no?–how can the distance from the cut slit to the unweighted end be 18″? Something here I’m not getting.
More importantly–how does the “air chuck” technique work? You take your tire-filling chuck and blast it–where? Upstream and away from the fuel, I presume? But how would a typical air chuck fit into a cut in a 1/2″ tube? Finally, won’t the gas leak all over the place from the slit, once it starts flowing?
Just curious.
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Maybe it’s a typo and the total hose length should be 10 feet? That’s the only thing I can think of. And the slit would be pointing up away from gravity flow once syphon starts. Wear eye protection
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